show solution 2x²-6x=3x
Answer:
To solve the equation \(2x^2 - 6x = 3x\), we'll first move all the terms to one side of the equation to set it to zero:
\[2x^2 - 6x - 3x = 0\]
This simplifies to:
\[2x^2 - 9x = 0\]
Next, we'll factor out the common term, which is \(x\):
\[x(2x - 9) = 0\]
Now, we have two possible solutions:
1. \(x = 0\)
2. \(2x - 9 = 0\) which leads to \(x = \frac{9}{2}\).
So, the solutions to the equation \(2x^2 - 6x = 3x\) are \(x = 0\) and \(x = \frac{9}{2}\).